Gibbs calculated required capacitive reactive power to raise PF to 0.90.
At 440 V, 60 Hz: Capacitance (C = \frac{Q_c}{2\pi f V^2} = \frac{3560}{2\pi \times 60 \times 440^2} \approx 48.7\ \mu\text{F}) per phase. examples in electrical calculations by admiralty pdf
Load current: (I = P/V = 3000/110 \approx 27.3\ \text{A}). The fuse was rated 40 A — fine for overload. But for short-circuit, the prospective fault current matters. Gibbs calculated required capacitive reactive power to raise
Cable data: 16 mm² copper, length 30 m round trip. Resistance: [ R_{cable} = \rho \times \frac{L}{A} = 0.0175 \times \frac{60}{16} \approx 0.0656\ \Omega ] examples in electrical calculations by admiralty pdf