Geometria Analitica Conamat Ejercicios Resueltos May 2026

: ( m = 2 ) 4. Equation of a Line (Point-Slope Form) Formula : [ y - y_1 = m(x - x_1) ] ✅ Solved Exercise 4 Find the line equation with slope ( m = -3 ) passing through ( (2, 5) ).

: Complete the square: [ y = 2(x^2 - 4x) + 5 = 2(x^2 - 4x + 4 - 4) + 5 ] [ y = 2[(x - 2)^2 - 4] + 5 = 2(x - 2)^2 - 8 + 5 = 2(x - 2)^2 - 3 ] Rewrite: [ y + 3 = 2(x - 2)^2 \implies (x - 2)^2 = \frac12(y + 3) ] So ( 4p = \frac12 \implies p = \frac18 ). geometria analitica conamat ejercicios resueltos

: [ d = \sqrt(7 - 3)^2 + (5 - 2)^2 = \sqrt4^2 + 3^2 = \sqrt16 + 9 = \sqrt25 = 5 ] : ( m = 2 ) 4