def extract_metadata(file_name): pattern = r"(.*)\.(\d{4})\.(.*)\.(.*)" match = re.match(pattern, file_name) if match: return { "title": match.group(1), "year": match.group(2), "resolution": match.group(3), "codec": match.group(4), } return {}

# Example usage file_name = "Road.House.2024.2160p.WEB.H265-McGregorBetterAc..." metadata = extract_metadata(file_name) print(metadata) This example illustrates a simple approach to extracting metadata from a file name. Depending on the chosen feature, the implementation details would significantly differ.

Choose currency
Menu
Search

Road.house.2024.2160p.web.h265-mcgregorbetterac... Online

def extract_metadata(file_name): pattern = r"(.*)\.(\d{4})\.(.*)\.(.*)" match = re.match(pattern, file_name) if match: return { "title": match.group(1), "year": match.group(2), "resolution": match.group(3), "codec": match.group(4), } return {}

# Example usage file_name = "Road.House.2024.2160p.WEB.H265-McGregorBetterAc..." metadata = extract_metadata(file_name) print(metadata) This example illustrates a simple approach to extracting metadata from a file name. Depending on the chosen feature, the implementation details would significantly differ. Road.House.2024.2160p.WEB.H265-McGregorBetterAc...

Sign up for our weekly newsletter and we will keep you updated with inspiration, news and exclusive offers.

This site uses cookies (cookies) to ensure the best user experience. If you continue to use the site, you accept the use of cookies. Read more »

Ok