Solucionario Amplificadores Operacionales Y Circuitos Integrados Lineales Robert F. Coughlin 1 » 【Trusted】

: Design a circuit that outputs (V_out = -(2V_1 + V_2 + 0.5V_3)). → Choose (R_f = 10k\Omega), then (R_1=5k\Omega), (R_2=10k\Omega), (R_3=20k\Omega). 3. Solving Integrator & Differentiator Circuits (Chapter 5) 📌 Integrator (Miller integrator) [ V_out(t) = -\frac1RC \int V_in(t) dt + V_out(0) ]

(instrumentation amplifier configuration): [ V_out = \fracR_fR_1(V_2 - V_1) = \frac100k10k(1.05 - 1.0) = 10 \times 0.05 = 0.5V ] : Design a circuit that outputs (V_out = -(2V_1 + V_2 + 0

: If (R_f=0) or (R_1=\infty), it becomes a voltage follower ((V_out=V_in)). 🔹 Summing Amplifier (Chapter 3) For an inverting summer with three inputs: [ V_out = -R_f\left(\fracV_1R_1 + \fracV_2R_2 + \fracV_3R_3\right) ] Adjust for (Q)

: Design a low-pass filter with (f_c = 1kHz), (Q=0.707) (Butterworth). → Use (R_1=R_2=10k\Omega), then (C_1=C_2=\frac12\pi(10k)(1k) \approx 15.9nF). Adjust for (Q). 5. Solving Comparator & Schmitt Trigger (Chapter 8) Non-inverting Schmitt trigger Upper threshold: [ V_UT = \fracR_1R_1+R_2 V_sat^+ ] Lower threshold: [ V_LT = \fracR_1R_1+R_2 V_sat^- ] Hysteresis (= V_UT - V_LT). (Q=0.707) (Butterworth). → Use (R_1=R_2=10k\Omega)