Edition Beer Johnston Solution 1 | Vector Mechanics Dynamics 9th

The x-component of $F_1$ is: $F_{1x} = F_1 \cos 30^\circ = 100 \cos 30^\circ = 86.60 \text{ N}$

The x-component of the resultant force $R$ is: $R_x = F_{1x} + F_{2x} = 86.60 + 75 = 161.60 \text{ N}$ The x-component of $F_1$ is: $F_{1x} = F_1

The magnitude of the resultant force $R$ is: $R = \sqrt{R_x^2 + R_y^2} = \sqrt{(161.60)^2 + (179.90)^2} = 242.11 \text{ N}$ The x-component of $F_1$ is: $F_{1x} = F_1

The magnitude of the resultant force $R$ is $242.11 \text{ N}$. The x-component of $F_1$ is: $F_{1x} = F_1